Repository: amalpoulose/Zoho-Interview-questions
Branch: master
Commit: d8198cb7c2c1
Files: 32
Total size: 76.8 KB
Directory structure:
gitextract_5u_4w79b/
├── .gitignore
├── LICENSE
├── README.md
├── Set 01 Qns.txt
├── Set 01-01.print the following pattern.c
├── Set 01-02.find sum of weights based on the following conditions.c
├── Set 01-03.Save the string in a two dimensional array and search for substring.c
├── Set 01-05.find no of grandchildren.c
├── Set 02-01.Alternate sorting.c
├── Set 02-01.Alternate sorting.py
├── Set 02-02.Remove unbalanced parentheses in a given expression.c
├── Set 02-02.Remove unbalanced parentheses in a given expression.py
├── Set 02-03.Form a number system with only 3 and 4.c
├── Set 02-qns
├── Set 03-01.program to give the following output.c
├── Set 03-02.sort the elements in odd positions in descending order and elements in ascending order.c
├── Set 03-03.program to print the following output for the given input.c
├── Set 03-05-01.two sorted arrays, merge them such that the elements are not repeated.c
├── Set 03-05-02.two sorted arrays, merge them such that the elements are not repeated.c
├── Set 03-Qns
├── Set 08 Qns
├── Set 08 Qns2
├── Set 08-01.Spiral printing.c
├── Set 08-02.Two strings of equal length are given print the mismatched ones..c
├── Set 08-03.Get a number and check whether its palindrome do not use arrays and string manipulations.c
├── Set 12-01.Given two numbers a and b both < 200 we have to find the square numbers which lie between a and b.c
├── Set 12-03.Given an array and a threshold value find the output.c
├── Set 12-05.Write a program to print the below pattern.c
├── Set 12-06.Given bigger NxN matrix and a smaller MxM matrix print TRUE if the smaller matrix can be found in the bigger matrix else print FALSE.c
├── Set 12-07.Given two matrices a and b both of size NxN find if matrix a can be transformed to matrix b by rotating it 90deg , 180deg , 270deg if so print TRUE else print FALSE.c
├── Set 12-08.In addition to the above question you have to check if matrix a can be transformed by mirroring vertically or horizontally to matrix b..c
└── Set 12-Qns
================================================
FILE CONTENTS
================================================
================================================
FILE: .gitignore
================================================
# Prerequisites
*.d
# Object files
*.o
*.ko
*.obj
*.elf
# Linker output
*.ilk
*.map
*.exp
# Precompiled Headers
*.gch
*.pch
# Libraries
*.lib
*.a
*.la
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# Shared objects (inc. Windows DLLs)
*.dll
*.so
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*.dylib
# Executables
*.exe
*.out
*.app
*.i*86
*.x86_64
*.hex
# Debug files
*.dSYM/
*.su
*.idb
*.pdb
# Kernel Module Compile Results
*.mod*
*.cmd
.tmp_versions/
modules.order
Module.symvers
Mkfile.old
dkms.conf
================================================
FILE: LICENSE
================================================
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DATA OR DATA BEING RENDERED INACCURATE OR LOSSES SUSTAINED BY YOU OR THIRD
PARTIES OR A FAILURE OF THE PROGRAM TO OPERATE WITH ANY OTHER PROGRAMS),
EVEN IF SUCH HOLDER OR OTHER PARTY HAS BEEN ADVISED OF THE POSSIBILITY OF
SUCH DAMAGES.
17. Interpretation of Sections 15 and 16.
If the disclaimer of warranty and limitation of liability provided
above cannot be given local legal effect according to their terms,
reviewing courts shall apply local law that most closely approximates
an absolute waiver of all civil liability in connection with the
Program, unless a warranty or assumption of liability accompanies a
copy of the Program in return for a fee.
END OF TERMS AND CONDITIONS
How to Apply These Terms to Your New Programs
If you develop a new program, and you want it to be of the greatest
possible use to the public, the best way to achieve this is to make it
free software which everyone can redistribute and change under these terms.
To do so, attach the following notices to the program. It is safest
to attach them to the start of each source file to most effectively
state the exclusion of warranty; and each file should have at least
the "copyright" line and a pointer to where the full notice is found.
{one line to give the program's name and a brief idea of what it does.}
Copyright (C) {year} {name of author}
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
Also add information on how to contact you by electronic and paper mail.
If the program does terminal interaction, make it output a short
notice like this when it starts in an interactive mode:
{project} Copyright (C) {year} {fullname}
This program comes with ABSOLUTELY NO WARRANTY; for details type `show w'.
This is free software, and you are welcome to redistribute it
under certain conditions; type `show c' for details.
The hypothetical commands `show w' and `show c' should show the appropriate
parts of the General Public License. Of course, your program's commands
might be different; for a GUI interface, you would use an "about box".
You should also get your employer (if you work as a programmer) or school,
if any, to sign a "copyright disclaimer" for the program, if necessary.
For more information on this, and how to apply and follow the GNU GPL, see
<http://www.gnu.org/licenses/>.
The GNU General Public License does not permit incorporating your program
into proprietary programs. If your program is a subroutine library, you
may consider it more useful to permit linking proprietary applications with
the library. If this is what you want to do, use the GNU Lesser General
Public License instead of this License. But first, please read
<http://www.gnu.org/philosophy/why-not-lgpl.html>.
================================================
FILE: README.md
================================================
# Zoho-Interview-questions
previous zoho interview questions
================================================
FILE: Set 01 Qns.txt
================================================
SET 1
Second Round: (Normal Programming round)
1. Print the word with odd letters as
P M
R A
O R
G
O R
R A
P M
2. Given a set of numbers like <10, 36, 54,89,12> we want to find sum of weights based on the following conditions
1. 5 if a perfect square
2. 4 if multiple of 4 and divisible by 6
3. 3 if even number
And sort the numbers based on the weight and print it as follows
<10,its_weight>,<36,its weight><89,its weight>
Should display the numbers based on increasing order.
3. Save the string “WELCOMETOZOHOCORPORATION” in a two dimensional array and search for substring like “too” in the two dimensional string both from left to right and from top to bottom.
w e L C O
M E T O Z
O H O C O
R P O R A
T I O n
And print the start and ending index as
Start index : <1,2>
End index: <3, 2>
4. Given a 9×9 sudoku we have to evaluate it for its correctness. We have to check both the sub matrix correctness and the whole sudoku correctness.
5. Given a two dimensional array of string like
<”luke”, “shaw”>
<”wayne”, “rooney”>
<”rooney”, “ronaldo”>
<”shaw”, “rooney”>
Where the first string is “child”, second string is “Father”. And given “ronaldo” we have to find his no of grandchildren Here “ronaldo” has 2 grandchildren. So our output should be 2.
Third Round: (Advanced Programming Round)
Here they asked us to create a “Railway reservation system” and gave us 4 modules. The modules were:
1. Booking
2. Availability checking
3. Cancellation
4. Prepare chart
We were asked to create the modules for representing each data first and to continue with the implementation phase.
================================================
FILE: Set 01-01.print the following pattern.c
================================================
/* To print the following pattern
P M
R A
O R
G
O R
R A
P M */
#include<stdio.h>
int main(void)
{
char str[100],i,j,k,n;
printf("Enter the string : ");
scanf("%s",str);
for(n=-1;str[n];n++);
if(n%2==0)
{
printf("\n\nString length is even\n\n");
return;
}
n=n/2+1;
for(i=1;i<=n;i++)
{
k=0;
for(j=1;j<i;j++)
printf(" ");
for(j=1;j<=2*(n-i)+1;j++)
{ if(j==1 || j==2*(n-i)+1)
printf("%c",str[i-1+k]);
else
printf(" ");
k++;
}
printf("\n");
}
for(i=2;i<=n;i++)
{
k=0;
for(j=1;j<=n-i;j++)
printf(" ");
for(j=1;j<=2*i-1;j++)
{
if(j==1 || j==2*i-1)
printf("%c",str[n-i+k]);
else
printf(" ");
k++;
}
printf("\n");
}
}
================================================
FILE: Set 01-02.find sum of weights based on the following conditions.c
================================================
/* Given a set of numbers like <10,36,54,89,12> we want to find sum of weights based on the following conditions
1. 5 if a perfect square
2. 4 if multiple of 4 and divisible by 6
3. 3 if even number
And sort the numbers based on the weight and print it as follows
<10,its_weight>,<36,its weight><89,its weight>
Should display the numbers based on increasing order*/
#include<stdlib.h>
#include<stdio.h>
int check(int);
int main(void)
{
int *a,i,j,n;
printf("Array size : ");
scanf("%d",&n);
a=malloc(sizeof(int)*n);
printf("Enter array elements : ");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
printf("Array elements : ");
for(i=0;i<n;i++)
printf("%d ",a[i]);
for(i=0;i<n-1;i++)
for(j=0;j<n-i-1;j++)
if(check(a[j])>check(a[j+1]))
a[j]=a[j]+a[j+1]-(a[j+1]=a[j]);
printf("The elements after sorting with its weight is : \n");
for(i=0;i<n;i++)
printf("< %d , %d >\n",a[i],check(a[i]));
free(a);
return 0;
}
int check(int n)
{
int sum,weight=0,i;
for(sum=0,i=1;i<n;i+=2)
{
sum=sum+i;
if(sum==n)
weight+=5;
}
if(n%4==0 && n%6==0)
weight+=4;
if(n%2==0)
weight+=3;
return weight;
}
================================================
FILE: Set 01-03.Save the string in a two dimensional array and search for substring.c
================================================
/* Save the string “WELCOMETOZOHOCORPORATION” in a two dimensional array and search for substring like “too” in the two dimensional string both from left to right and from top to bottom.
w e L C O
M E T O Z
O H O C O
R P O R A
T I O n
And print the start and ending index as
Start index : <1,2>
End index: <3, 2>*/
#include<stdio.h>
int sqt(float);
int main(void)
{
// a is 2d array to store the sting
char str[100],str1[100],a[100][100];
//main variables inx =index of string n= length of string rc=number of rows and coloumn(square matrix)
int n,rc,i,j,inx,k,c;
//enter main string to str
printf("Enter the string : ");
scanf("%s",str);
//find length of string
for(n=0;str[n];n++);
// find row and coloumn size by taking square root of n(length of string
if(n=sqt(n)*sqt(n))
rc=sqt(n)+1;
else
rc=sqt(n);
//enter each character in to 2 diamensional array
for(inx=0,i=0;i<rc ;i++)
for(j=0;j<rc && str[inx];j++)
{
a[i][j]=str[inx++];
}
// print contents of 2d array
for(i=0;i<rc;i++)
{
for(j=0;j<rc;j++)
printf("%c ",a[i][j]);
printf("\n");
}
//Enter the substring as str1
printf("Enter word to found : ");
scanf("%s",str1);
//find substring in rows
for(i=0;i<rc;i++)
for(j=0;j<rc;j++)
if(a[i][j]==str1[0])
{ for(k=j,c=0;a[i][k]==str1[c] && a[i][k]!='\0';k++,c++);
if(str1[c]=='\0'){
printf("\nStart index : <%d ,%d> End index: <%d, %d>\n",i,j,i,k-1);}
}
//find substring in coloumns
for(i=0;i<rc;i++)
for(j=0;j<rc;j++)
if(a[j][i]==str1[0])
{
for(k=j,c=0;a[k][i]==str1[c] && a[k][i]!='\0';k++,c++);
if(str1[c]=='\0'){
printf("\nStart index : <%d ,%d> End index: <%d, %d>\n",j,i,k-1,i);}
}
return 0;
}
//user defined function to find square root by Babylonian method
int sqt(float n)
{
float x=n,y=1;
while(x-y>0.00001)
{
x=(x+y)/2;
y=n/x;
}
return x;
}
================================================
FILE: Set 01-05.find no of grandchildren.c
================================================
/* Given a two dimensional array of string like
<”luke”, “shaw”>
<”wayne”, “rooney”>
<”rooney”, “ronaldo”>
<”shaw”, “rooney”>
Where the first string is “child”, second string is “Father”.
And given “ronaldo” we have to find his no of grandchildren Here “ronaldo” has 2 grandchildren.
So our output should be 2. */
#include<stdlib.h>
#include<stdio.h>
int main(void)
{
char *str,***a;
str=malloc(50);
int n,i,j,c=0;
//enter th number of pair of strings
printf("Enter the number of pair : ");
scanf("%d",&n);
//create 3d array dynamically using malloc
a=malloc(sizeof(char*)*n); //allocate n character pointer spaces and store addres in a
for(i=0;i<n;i++)
{ a[i]=malloc(sizeof(char*)*2); // store 2 chara pointer spaces to every previously allocated n spaces
for(j=0;j<2;j++)
a[i][j]=malloc(sizeof(char)*50); // allocate 50 bytes to previously allocated 2 char pointer spaces
}
//enter the list of strings
printf("Enter the strings : ");
for(i=0;i<n;i++)
{
for(j=0;j<2;j++)
scanf(" %s",a[i][j]);
}
//print length of strings
printf("The Array is : \n");
for(i=0;i<n;i++)
{
printf("<");
for(j=0;j<2;j++)
printf("%-10s ",a[i][j]);
printf(">\n");
}
//enter the grangfather name
printf("Enter the string : ");
scanf("%s",str);
printf("Grandchildren of %s : ",str);
for(i=0;i<n;i++)
if(strcmp(a[i][1],str)==0) //Locate grandfather in the list
for(j=0;j<n;j++) // Find son of the grandfather
if(strcmp(a[j][1],a[i][0])==0) //find grandchildren
{ printf("%s ",a[j][0]);
c++; //increment count for every grandchildren
}
printf("\nNumber of grandchildren : %d\n",c);
free(a);
free(str);
return 0;
}
================================================
FILE: Set 02-01.Alternate sorting.c
================================================
/* Alternate sorting: Given an array of integers, rearrange the array in such a way that the first element is first maximum and second element is first minimum.
Eg.) Input : {1, 2, 3, 4, 5, 6, 7}
Output : {7, 1, 6, 2, 5, 3, 4} */
#include<stdio.h>
int main(void)
{
int a[100],i,j,n,t;
printf("Array size : ");
scanf("%d",&n);
printf("Enter array elements : ");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
printf("Array elements : \n");
for(i=0;i<n;i++)
printf("%d ",a[i]);
printf("\n");
/* Selection sort is used because the 1st element would be fixed after one iteration of outer loop*/
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++)
{
if(i%2) // if i value is odd then smallest value in remaining index values is goes to ith index
{ if(a[i]>a[j])
a[i]=a[i]+a[j]-(a[j]=a[i]);
}
else // if i value is even then largest value in remaining index values is goes to ith index
{
if(a[i]<a[j])
a[i]=a[i]+a[j]-(a[j]=a[i]);
}
}
printf("Array elements : \n");
for(i=0;i<n;i++)
printf("%d ",a[i]);
printf("\n");
return 0;
}
================================================
FILE: Set 02-01.Alternate sorting.py
================================================
#!/usr/bin/python
''' Alternate sorting: Given an array of integers, rearrange the array in such a way that the first element is first maximum and second element is first minimum.
Eg.) Input : {1, 2, 3, 4, 5, 6, 7}
Output : {7, 1, 6, 2, 5, 3, 4}'''
arr=[]
def main():
arr_size=input("array size : ")
print "elements : "
for i in range(arr_size):
arr.append(input())
for i in range(len(arr)-1):
if i%2==0:
for j in range(i,len(arr)):
if arr[i]<arr[j]:
arr[i],arr[j]=arr[j],arr[i]
else:
for j in range(i,len(arr)):
if arr[i]>arr[j]:
arr[i],arr[j]=arr[j],arr[i]
print arr
if __name__=="__main__":
main()
================================================
FILE: Set 02-02.Remove unbalanced parentheses in a given expression.c
================================================
/* Remove unbalanced parentheses in a given expression.
Eg.) Input : ((abc)((de))
Output : ((abc)(de))
Input : (a(b)))(cd)
Output : (a(b))(cd)
Input : (a(b)))(c(d)
Output : (a(b))(cd)
Input : (ab))(c(d))))
Output : (ab)(c(d))
Input : (((ab)
Output : (ab)
*/
#include<stdio.h>
int main(void)
{
char str[100];
int i,j,end=0;
printf("enter the string : ");
scanf("%s",str);
for(i=0;str[i];i++)
{
if(str[i]=='(')
{
for(end+=1;str[end]!=')'&&str[end]!='\0';end++);
if(str[end]=='\0') //remove unbalanced '(' at any position
{
for(j=i;str[j]=str[j+1];j++);
i--;
}
if(end<i)
{
for(j=end;str[j]=str[j+1];j++); //remove unbalanced ')' at middle position
i-=1;
}
}
if(str[i]==')') //remove unbalanced ')' at last positions
if(i>end || i==0)
{
for(j=i;str[j]=str[j+1];j++);
i--;}
}
printf("New string is : %s\n",str);
return 0;
}
================================================
FILE: Set 02-02.Remove unbalanced parentheses in a given expression.py
================================================
#!/usr/bin/python
#Remove unbalanced parentheses in a given expression
def remove(s,index):
s=s[:index]+s[index+1:]
return s
def main():
s=raw_input("string : ")
start,stop=0,0
while s[start:].find('(') != -1:
index=s[start:].find('(')+start
while s[stop:index].find(')')!=-1:
s=remove(s,s[stop:].find(')')+stop)
index-=1
if s[stop:].find(')') == -1:
s=remove(s,index)
else:
stop=s[stop:].find(')')+stop+1
start=index+1
while s[stop:].find(')')!= -1:
s=remove(s,s[stop:].find(')')+stop)
print "formatted string : ",s
if __name__=="__main__":
main()
================================================
FILE: Set 02-03.Form a number system with only 3 and 4.c
================================================
/* C) Form a number system with only 3 and 4. Find the nth number of the number system.
Eg.) The numbers are: 3, 4, 33, 34, 43, 44, 333, 334, 343, 344, 433, 434, 443, 444, 3333, 3334, 3343, 3344, 3433, 3434, 3443, 3444 ….
*/
#include<stdio.h>
int main(void)
{
int n,i,m,pos,tmp=1,num_dgs;
printf("Enter the value n : ");
scanf("%d",&n);
m=n;
for(i=-1;m;m/=2,i++); //find number of digits
num_dgs=i;
for(;i;i--) //find nearest value which is power of two
tmp*=2;
pos=n-tmp;
pos++; //find position of nth number in the class of num_digits
//eg: 11 is 4th number in 3 digits numbers
if(!num_dgs) //if n=1 when pos = 1 next step becomes number of digits 1 and position 0
pos=1;
if(pos==tmp){ //In cases for example n=7 we have to make number of digits 3 instead of 2 and pos 0
pos=0;
num_dgs++;
}
printf("The %dth number in sequence is : ",n);
for(i=num_dgs-1;i>=0;i--) //loop in which where 1 is present in bits of pos prints 4 and where 0 print 3
if((pos>>i)&1)
printf("4");
else
printf("3");
printf("\n");
return 0;
}
================================================
FILE: Set 02-qns
================================================
Set 2
1) First Round : Written
40 C output questions. 2 Hours.
30 1Mark and 10 2Mark questions. IT WAS NOT MCQ. The questions were challenging and covered all C concepts.
2) Second Round : Coding
Around 150 students shortlisted for this round. It was a local machine coding round. A staff will be assigned to a group of 5 students. He made note of the time took for solving each question. There was totally 7 questions and I solved 4 questions and did not complete the 5th question.
A) Alternate sorting: Given an array of integers, rearrange the array in such a way that the first element is first maximum and second element is first minimum.
Eg.) Input : {1, 2, 3, 4, 5, 6, 7}
Output : {7, 1, 6, 2, 5, 3, 4}
B) Remove unbalanced parentheses in a given expression.
Eg.) Input : ((abc)((de))
Output : ((abc)(de))
Input : (((ab)
Output : (ab)
C) Form a number system with only 3 and 4. Find the nth number of the number system.
Eg.) The numbers are: 3, 4, 33, 34, 43, 44, 333, 334, 343, 344, 433, 434, 443, 444, 3333, 3334, 3343, 3344, 3433, 3434, 3443, 3444 ….
D) Check whether a given mathematical expression is valid.
Z
Eg.) Input : (a+b)(a*b)
Output : Valid
Input : (ab)(ab+)
Output : Invalid
Input : ((a+b)
Output : Invalid
I don’t remember the 5th question.
3) Third Round : Advanced Coding
A matrix game was given with 5 rules. We were asked to implement each of the rules separately.
R3 | - - - |
R2 | - - - |
R1 | - - - |
C1 C2 C3
Each of the 9 cells can either be empty or filled with an atom. R3, R2, R1 are the rays that originate from the left. C1, C2, C3 are the rays that originate from the bottom of the box.
Input : Position of the atoms and the rays that gets originated from the outside of the box.
Eg.) 3
3 1
2 2
1 3
3
R3 C1 C3
Output : Print the box.
Rule 1:
A ray that has an atom in its path should print ‘H’ (Hit) If it does not have any atoms in its path, the ray should pass to the other side.
C1 C3
R3 | - - - | R3
H | - X - |
R1 | - - - | R1
C1 H C3
Rule 2 & 3:
A ray that has an atom in its diagonal adjacent position should refract.
H | - - - |
H | X - - |
R | - X - |
R H R
Input rays: R1, R2, C3
H | - X - |
R2 | - - - | C3
| - - - |
R2 C3
Rule 4:
A ray that has atoms in both of the diagonal adjacent positions should reflect back.
Input ray: C2
| - - - |
| X - X |
| - - - |
R
Input ray: R2
| - X - |
R | - - - |
| - X - |
Rule 5:
The deflection of rays should happen in the order of the input rays.
Input Rays: R3, R2, C1, C3
H | - X - |
R2 | - - - | C3
| - - - |
R2 C3
The final task was to implement these rules for dynamic matrix size.
Input : no of rows, no of columns
Eg.) 4 4 (row & column)
2 (No of atoms)
4 4 (Position of atom)
2 2 (Position of atom)
2 (No of rays)
R4 C2 (Ray number)
H | - - - X |
| - - - - |
| - X - - |
| - - - - |
H
The final task was very confusing and it had to handle all the cases. There are chances for a ray to end at the starting position if the number of rows and columns are more than 5.
4) Fourth Round : Technical Interview
Basic questions from hashing, searching, sorting, JVM, OS, Threads. In-depth questions from the projects that I mentioned in my resume. So don’t just add projects that you are not thorough enough to answer all questions.
And a simple puzzle : (x-a)(x-b)(x-c)….(x-z) = ? 😀
5) Fifth Round : HR
General HR questions like why zoho, how do you see yourself after 5 years, why did you choose CS/IT stream, tell me about your leadership skills etc.
================================================
FILE: Set 03-01.program to give the following output.c
================================================
/* 1. Write a program to give the following output for the given input
Eg 1: Input: a1b10
Output: abbbbbbbbbb
Eg: 2: Input: b3c6d15
Output: bbbccccccddddddddddddddd
The number varies from 1 to 99.*/
#include<stdlib.h>
#include<stdio.h>
int main(void)
{
char *str,last;
int i,n=0;
str=malloc(100);
printf("Enter the string : ");
scanf("%s",str);
for(i=0;str[i];i++)
{
if(str[i]<48||str[i]>57)
{
printf("%c",str[i]); //print characters other than integer value and continue the loop
continue;
}
for(last=i;(str[i]>=48&&str[i]<=57)&&str[i];i++) //Loop to find integer value store it in n
n=n*10+(str[i]-48);
i--;
if(last) //if first value is integer that is last = 0 do nothing simply put n=0 in else part
for(n-=1;n;n--) //Loop to print n times the character
printf("%c",str[last-1]);
else n=0;
}
printf("\n");
free(str);
return 0;
}
================================================
FILE: Set 03-02.sort the elements in odd positions in descending order and elements in ascending order.c
================================================
/* 2. Write a program to sort the elements in odd positions in descending order and elements in ascending order
Eg 1: Input : 13,2 4,15,12,10,5
Output: 13,2,12,10,5,15,4
Eg 2: Input : 1,2,3,4,5,6,7,8,9
Output: 9,2,7,4,5,6,3,8,1
*/
#include<stdio.h>
#include<stdlib.h>
int main(void)
{
int *a,n,i,j;
printf("Array size : ");
scanf("%d",&n);
a=malloc(sizeof(int)*n);
printf("Enter Elements : ");
for(i=0;i<n;i++)
scanf("%d",a+i);
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++)
{
if(i%2)
{
if(a[i]>a[j])
a[i]=a[i]+a[j]-(a[j]=a[i]);
}
else
{
if(a[i]<a[j])
a[i]=a[i]+a[j]-(a[j]=a[i]);
}
}
printf("Array elements : ");
for(i=0;i<n;i++)
printf("%d ",a[i]);
printf("\n");
free(a);
return 0;
}
================================================
FILE: Set 03-03.program to print the following output for the given input.c
================================================
/*3. Write a program to print the following output for the given input. You can assume the string is of odd length
Eg 1: Input: 12345
Output:
1 5
2 4
3
2 4
1 5
Eg 2: Input: geeksforgeeks
Output:
g s
e k
e e
k e
s g
f r
o
f r
s g
k e
e e
e k
g s
*/
#include<stdio.h>
int main(void)
{
char str[50];
int i,j,n;
printf("Enter the string : ");
scanf("%s",str);
for(n=0;str[n];n++);
n=n/2+1;
for(i=1;i<=n;i++)
{
for(j=1;j<i;j++)
printf(" ");
for(j=0;j<2*(n-i)+1;j++)
if(j==0 || j==2*(n-i))
printf("%c",str[i-1+j]);
else
printf(" ");
printf("\n");
}
for(i=2;i<=n;i++)
{
for(j=1;j<=n-i;j++)
printf(" ");
for(j=1;j<=2*i-1;j++)
if(j==1 || j==2*i-1)
printf("%c",str[n-i-1+j]);
else
printf(" ");
printf("\n");
}
return 0;
}
================================================
FILE: Set 03-05-01.two sorted arrays, merge them such that the elements are not repeated.c
================================================
/* 5. Given two sorted arrays, merge them such that the elements are not repeated
Eg 1: Input:
Array 1: 2,4,5,6,7,9,10,13
Array 2: 2,3,4,5,6,7,8,9,11,15
Output:
Merged array: 2,3,4,5,6,7,8,9,10,11,13,15 */
/* Procedure 1 : Remove repeated terms and saving into third array(lengthy)*/
#include<stdio.h>
int main(void)
{
int a[100],b[100],c[100],i,j,k,m,n;
printf("\n---------------------------------------------------------------\n");
printf("Array size 1: ");
scanf("%d",&m);
printf("Elements to array 1 : \n");
for(i=0;i<m;i++)
scanf("%d",&a[i]);
printf("Array size 2: ");
scanf("%d",&n);
printf("Elements to array 2 : \n");
for(i=0;i<n;i++)
scanf("%d",&b[i]);
printf("\n---------------------------------------------------------------\n");
printf("\nArray 1 elements :");
for(i=0;i<m;i++)
printf("%d ",a[i]);
printf("\nArray 2 elements :");
for(i=0;i<n;i++)
printf("%d ",b[i]);
for(i=0,j=0,k=0;i<m && j<n;k++)
{
if(b[j]<a[i]) //element of array b is smaller then true
{
if(c[k-1]==b[i]) //if previous element in 3rd array is current element then discard it otherwise save it into 3rd array
i++;
else{
c[k]=b[j];
j++;
}
}
else if(a[i]<b[j]) //element of array a is smaller then true
{
if(c[k-1]==a[i]) //if previous element in 3rd array is current element then discard it otherwise save it into 3rd array
i++;
else
{
c[k]=a[i];
i++;
}
}
else if(a[i]==b[j]) // if both elements in array a and b are equal then true
{
if(c[k-1]==a[i]){ //if previous element in 3rd array is current element then discard it otherwise save it into 3rd array
i++;j++;k--;
}
else{
c[k]=a[i];
i++;
j++;
}
}
}
while(i<m || j<n) // if m and n are different values the remaing values must store into 3rd array
{
if(i<m) //if i<m true only 1st array elements remaining
{
if(c[k-1]==a[i]) //if previous element in 3rd array is current element then discard it otherwise save it into 3rd array
i++;
else
{
c[k]=a[i];
i++;
k++;
}
}
if(j<n) //if i<m true only 1st array elements remaining
{
if(c[k-1]==b[j]) //if previous element in 3rd array is current element then discard it otherwise save it into 3rd array
j++;
else
{
c[k]=b[j];
j++;
k++;
}
}
}
printf("\nArray 3 elements :");
for(i=0;i<k;i++)
printf("%d ",c[i]);
printf("\n");
printf("\n---------------------------------------------------------------\n");
return 0;
}
================================================
FILE: Set 03-05-02.two sorted arrays, merge them such that the elements are not repeated.c
================================================
/*5. Given two sorted arrays, merge them such that the elements are not repeated
Eg 1: Input:
Array 1: 2,4,5,6,7,9,10,13
Array 2: 2,3,4,5,6,7,8,9,11,15
Output:
Merged array: 2,3,4,5,6,7,8,9,10,11,13,15 */
/*Procedure 2 : Saving both array into 3rd array and removing repeated terms*/
#include<stdio.h>
int main(void)
{
int a[100],b[100],c[100],i,j,k,l,m,n;
printf("\n---------------------------------------------------------------\n");
printf("Array size 1: ");
scanf("%d",&m);
printf("Elements to array 1 : \n");
for(i=0;i<m;i++)
scanf("%d",&a[i]);
printf("Array size 2: ");
scanf("%d",&n);
printf("Elements to array 2 : \n");
for(i=0;i<n;i++)
scanf("%d",&b[i]);
printf("\n---------------------------------------------------------------\n");
printf("\nArray 1 elements :");
for(i=0;i<m;i++)
printf("%d ",a[i]);
printf("\nArray 2 elements :");
for(i=0;i<n;i++)
printf("%d ",b[i]);
for(i=0;i<m;c[i]=a[i],i++); //save array 1 elements to array 3
for(j=0;j<n;c[i]=b[j],i++,j++);//save array 2 elements to array 3
l=m+n; //l is length of array 3
for(i=0;i<l;i++)
for(j=i+1;j<l;j++)
if(c[i]==c[j]) // if repeating terms found in array 3
{
for(k=j;k<l-1;c[k]=c[k+1],k++); //delete repeating terms
l--; //reduce length of array 3 by one
j--; //j reduces by one to continue on same jth iteration
}
printf("\nArray 3 elements :");
for(i=0;i<l;i++)
printf("%d ",c[i]);
printf("\n");
printf("\n---------------------------------------------------------------\n");
return 0;
}
================================================
FILE: Set 03-Qns
================================================
Set 3
ROUND 1: WRITTEN
APTITUDE(1 hr and 20 minutes-20 questions): Problems on average, probability, time & distance, alligation&mixture,ratio, HCF & LCM and few a puzzles.
TECHNICAL(45 minutes-10 questions): Output for C questions. Practice questions in geekquiz.com and C output questions in geeksforgeeks.org. Questions in pointers, strings, matrix etc.
Nearly 60 students were selected out of 600 candidates. They didn’t select the top 60. They had a cutoff and those who cleared the cutoff were called for the next round
ROUND 2: SIMPLE CODING(3 hours)
1. Write a program to give the following output for the given input
Eg 1: Input: a1b10
Output: abbbbbbbbbb
Eg: 2: Input: b3c6d15
Output: bbbccccccddddddddddddddd
The number varies from 1 to 99.
2. Write a program to sort the elements in odd positions in descending order and elements in ascending order
Eg 1: Input: 13,2 4,15,12,10,5
Output: 13,2,12,10,5,15,4
Eg 2: Input: 1,2,3,4,5,6,7,8,9
Output: 9,2,7,4,5,6,3,8,1
3. Write a program to print the following output for the given input. You can assume the string is of odd length
Eg 1: Input: 12345
Output:
1 5
2 4
3
2 4
1 5
Eg 2: Input: geeksforgeeks
Output:
g s
e k
e e
k e
s g
f r
o
f r
s g
k e
e e
e k
g s
4. Find if a String2 is substring of String1. If it is, return the index of the first occurrence. else return -1.
Eg 1:Input:
String 1: test123string
String 2: 123
Output: 4
Eg 2: Input:
String 1: testing12
String 2: 1234
Output: -1
5. Given two sorted arrays, merge them such that the elements are not repeated
Eg 1: Input:
Array 1: 2,4,5,6,7,9,10,13
Array 2: 2,3,4,5,6,7,8,9,11,15
Output:
Merged array: 2,3,4,5,6,7,8,9,10,11,13,15
6. Using Recursion reverse the string such as
Eg 1: Input: one two three
Output: three two one
Eg 2: Input: I love india
Output: india love I
19 cleared this round and they were called for the next round. The next round took place on the next day
ROUND 3: COMPLEX CODING(3 hours)
1) Design a Call taxi booking application
-There are n number of taxi’s. For simplicity, assume 4. But it should work for any number of taxi’s.
-The are 6 points(A,B,C,D,E,F)
-All the points are in a straight line, and each point is 15kms away from the adjacent points.
-It takes 60 mins to travel from one point to another
-Each taxi charges Rs.100 minimum for the first 5 kilometers and Rs.10 for the subsequent kilometers.
-For simplicity, time can be entered as absolute time. Eg: 9hrs, 15hrs etc.
-All taxi’s are initially stationed at A.
-When a customer books a Taxi, a free taxi at that point is allocated
-If no free taxi is available at that point, a free taxi at the nearest point is allocated.
-If two taxi’s are free at the same point, one with lower earning is allocated
-Note that the taxi only charges the customer from the pickup point to the drop point. Not the distance it travels from an adjacent point to pickup the customer.
-If no taxi is free at that time, booking is rejected
Design modules for
1) Call taxi booking
Input 1:
Customer ID: 1
Pickup Point: A
Drop Point: B
Pickup Time: 9
Output 1:
Taxi can be allotted.
Taxi-1 is allotted
Input 2:
Customer ID: 2
Pickup Point: B
Drop Point: D
Pickup Time: 9
Output 1:
Taxi can be allotted.
Taxi-2 is allotted
(Note: Since Taxi-1 would have completed its journey when second booking is done, so Taxi-2 from nearest point A which is free is allocated)
Input 3:
Customer ID: 3
Pickup Point: B
Drop Point: C
Pickup Time: 12
Output 1:
Taxi can be allotted.
Taxi-1 is allotted
2) Display the Taxi details
Taxi No: Total Earnings:
BookingID CustomerID From To PickupTime DropTime Amount
Output:
Taxi-1 Total Earnings: Rs. 400
1 1 A B 9 10 200
3 3 B C 12 13 200
Taxi-2 Total Earnings: Rs. 350
2 2 B D 9 11 350
These were just sample inputs. It should work for any input that they give.
Those who finished both the modules within 3 hours and if it worked for all the inputs they give, those candidates were given extra modules to work with.
Only 9 candidates made it to the next round
ROUND 4 : FIRST FACE-TO-FACE(TECHNICAL)
Questions were on project, c, oops concepts, DBMS and a few puzzles. They might ask you more on new scenarios relating to your project.
ROUND 5: SECOND FACE-TO-FACE(TECHNICAL)
Question were on c, c++, java(like threads, synchronization etc.), Discussion about questions from first, second and third round. He even asked me to solve a few questions from the first round. He gave me a few puzzles to solve
ROUND 6: FIRST GENERAL HR
General questions about my pros and cons and discussion on my resume(be thorough with your resume). She finally asked me if I had any queries.
ROUND 7: SECOND GENERAL HR
She asked me some family details and gave some scenarios and asked me to what I will do in such situations(like if I am given the power to change 3 things in india, what all will I change) and a few general questions.
I didn’t get direct placement in ZOHO but I got an internship offer. If I perform well in my internship, I will get an offer. Round 3 was the toughest and if you perform exceptionally well and as they expect in that round, you will definitely make it through. Many thanks to geeksforgeeks.org for helping me out in my preparation.
================================================
FILE: Set 08 Qns
================================================
Zoho Interview | Set 8 (Off-Campus Drive for Project Trainee)
First Round:
Written, pen paper based. The candidate has to write the output for C programs and basic aptitude questions. Total 30 questions. Test duration was of 3 hours.
Description:
There were altogether 20 questions from C programs and 10 questions from logical aptitude. Questions from C programming basically focus on pointers (single pointer and pointer-to-pointer) manipulation, 75% of questions from pointers and rest from arrays and strings manipulation. The questions from logical aptitude was of moderate level difficulty ranging from probability to speed distance time calculations. Both section same marks weightage. I solved 13 from C and 7 from apti.
Second Round:
They shortlisted approx 40 students for the second round. The mail came after 15 days from first round. It was coding round, programming questions on their laptops in groups of 10 students in each room. Test duration was of 3 hours. The test was on 1 Feb 2016.
Description:
There were 5 questions. The instructor will check the code after solving each question, they may ask for reducing time/ space complexity, be ready for it.
1. Spiral printing.
O/P
4444444
4333334
4322234
4321234
4322234
4333334
4444444
2. Sort the array alternately i.e first element should be max value, second min value, third second max, third second min. Eg: arr[] = {1,2,3,4,5,6,7} O/P: {7,1,6,2,5,3,4} Note: no extra space and time complexity should be less;
3. Print all the substring of the given string.
4. Print the numbers which are mismatched from two array. Arr1 = {a b c d e f g h i}
arr2 ={ a b d e e g g i i}, O/P- cd, de, f, g, h, i.
5. Print all possible combinations from the given string.
The candidate who solved at least four out five are selected for next advance coding round.
Third Round:
Third round was followed immediately after completion of second round. 50% candidates were selected for this round which consists of advance programming question. One full fledge project consist of 7 modules which has to be done on their laptops. Test duration was of 3 hours. Test was on 1 Feb 2016.
Description:
There was one question for each candidate.
1. Develop a railway project which consist of 7 requirements modules. The modules includes booking of railway tickets, cancellation, route option, fare calculations, allotting/dealloting berth, coach position.
Some other questions given to students were online billing and shopping. The instructor may ask to change the requirements run time, you should be ready for it.
Fourth Round:
Fourth round was followed immediately after completion of third round. It was face to face interview round in which technical and HR questions were asked. Interview duration was of 20 mins for each student. It was on same day.
Description:
This round consist of face to face interview, they asked questions from Java collection framework and core java. Questions related to course project was also asked. Finally, all the round were finished at 8 pm.
================================================
FILE: Set 08 Qns2
================================================
Zoho Interview | Set 8 (On-Campus)
ROUND 1: Aptitude questions – both Quantitative aptitude and in programming. they were NOT MCQs
ROUND 2:
1. Arrange the numbers in descending order depending on the no. of factors available for each number.
I/P: {6,8,9}
O/P: {8,6,9} or {6,8,9}
Reason: factors of 8 (1,2,4,8), factors of 6 (1,2,3,6), factors of 9 (1,3,9).
2. Two strings of equal length are given print the mismatched ones.
I/P: a b c d e f g h i
a b d e e g g i i
O/P: cd , de //when two char are mismatched they should be printed together.
f , g
h , i
3. Get a number and check whether its palindrome do not use arrays and string manipulations
I/P: 5
O/P: 101-Palindrome
Reason: binary representation of 5 is 101 & it is a palindrome.
I/P: 10
O/P: Binary representation of 10 is 1010 –Not a palindrome
4. For any given matrix find the path from the start to the end which gives the maximum sum. Traverse only right or down.
Example: starting index is 15 (left top) and ending index is 10 (bottom right)
15 25 30
45 25 60
70 75 10
O/P:15->45->70->75->10 sum is 215
5. [ [‘Lava’ , ‘kusha] ,
[‘Rama’ , ‘Lava’] ,
[‘Lava ‘,’Ravanan’] ,
[‘Abi’ , ‘Lava’] ]
First string is the child & the second string is the parent. Print the no. of grand children available for the
given I/P.
I/P: Ravanan
O/P: 2
================================================
FILE: Set 08-01.Spiral printing.c
================================================
#include<stdio.h>
int main(void)
{
int i,j,n;
printf("Limit : ");
scanf("%d",&n);
for(i=n;i>=1;i--)
{
for(j=n;j>=i;j--)
printf("%d ",j);
for(j=1;j<(2*i)-1;j++)
printf("%d ",i);
for(j=i+1;j<=n;j++)
printf("%d ",j);
printf("\n");
}
for(i=2;i<=n;i++)
{
for(j=n;j>=i;j--)
printf("%d ",j);
for(j=1;j<(2*i)-1;j++)
printf("%d ",i);
for(j=i+1;j<=n;j++)
printf("%d ",j);
printf("\n");
}
}
================================================
FILE: Set 08-02.Two strings of equal length are given print the mismatched ones..c
================================================
#include<stdio.h>
int main(void)
{
char a[50],b[50];
int i,j,n,st=0;
printf("Array size : ");
scanf("%d",&n);
printf("Elements to array :");
for(i=0;i<n;i++)
scanf(" %c",&a[i]);
printf("Elements to array :");
for(i=0;i<n;i++)
scanf(" %c",&b[i]);
printf("----Output----\n");
for(i=0;i<n;i++)
{
if(a[i]!=b[i])
{
for(j=i;a[j]!=b[j] && j<n;j++)
printf("%c",a[j]);
printf(" , ");
for(;i<j;i++)
printf("%c",b[i]);
printf("\n");
}
}
return 0;
}
================================================
FILE: Set 08-03.Get a number and check whether its palindrome do not use arrays and string manipulations.c
================================================
#include<stdio.h>
int main(void)
{
int n,i,j=0,temp;
printf("Enter a Number : ");
scanf("%d",&n);
for(i=sizeof(int)*8-1;!(n>>i&1);i--);
for(;j<i;i--,j++)
if((n>>i&1)!=(n>>j&1))
break;
temp=i;
for(i+=j;i>=0;printf("%d",n>>i&1),i--);
if(temp<=j)
printf(" - Palindrome\n");
else
printf(" - Not Palindrome\n");
return 0;
}
================================================
FILE: Set 12-01.Given two numbers a and b both < 200 we have to find the square numbers which lie between a and b.c
================================================
#include<stdio.h>
int main(void)
{
int a,b,i;
printf("Lower NUmber : ");
scanf("%d",&a);
printf("Upper NUmber : ");
scanf("%d",&b);
printf("Perfect Square number between %d and %d is : ",a,b);
for(i=0;i*i<=a;i++);
for(;i*i<b;i++)
printf("%d ",i*i);
printf("\n");
return 0;
}
================================================
FILE: Set 12-03.Given an array and a threshold value find the output.c
================================================
#include<stdio.h>
int main(void)
{
int a[100],i,th,n,count=0,sum,temp;
printf("Array size : ");
scanf("%d",&n);
printf("Elements to Array : ");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
printf("Array elements : ");
for(i=0;i<n;i++)
printf("%d ",a[i]);
printf("\nThreshold value : ");
scanf("%d",&th);
for(i=0;i<n;i++)
{
temp=th;
sum=0;
while(sum!=a[i])
{
sum+=temp;
count++;
if(sum>a[i])
{
sum-=temp;
temp--;
count--;
}
}
}
printf("count = %d\n",count);
return 0;
}
================================================
FILE: Set 12-05.Write a program to print the below pattern.c
================================================
#include<stdio.h>
int main(void)
{
int n,i,j,k;
printf("Limit : ");
scanf("%d",&n);
for(i=0;i<n;i++)
{
k=i+1;
for(j=0;j<n-i;k+=n-j,j++)
printf("%2d ",k);
printf("\n");
}
return 0;
}
================================================
FILE: Set 12-06.Given bigger NxN matrix and a smaller MxM matrix print TRUE if the smaller matrix can be found in the bigger matrix else print FALSE.c
================================================
#include<stdio.h>
int main(void)
{
int a[50][50],b[50][50],r1,c1,r2,c2,i,j,k,l;
printf("Array 1 size : ");
scanf("%d%d",&r1,&c1);
printf("Elements to Array : ");
for(i=0;i<r1;i++)
for(j=0;j<c1;j++)
scanf("%d",&a[i][j]);
printf("Array elements : \n");
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
printf("%d ",a[i][j]);
printf("\n");
}
printf("Array 2 size : ");
scanf("%d%d",&r2,&c2);
printf("Elements to Array : ");
for(i=0;i<r2;i++)
for(j=0;j<c2;j++)
scanf("%d",&b[i][j]);
printf("Array elements : \n");
for(i=0;i<r2;i++)
{
for(j=0;j<c2;j++)
printf("%d ",b[i][j]);
printf("\n");
}
for(i=0;i<r1;i++)
for(j=0;j<c1;j++)
{
if(a[i][j]==b[0][0])
{
for(k=0;k<r2;k++)
for(l=0;l<c2;l++)
if(a[i+k][j+l]!=b[k][l])
goto EXIT;
EXIT:
if(k==r2 && l==c2)
{
printf("\nTRUE : <%d,%d> to <%d,%d>\n",i,j,i+k-1,j+l-1);
return;
}
}
}
printf("\n False\n");
return 0;
}
================================================
FILE: Set 12-07.Given two matrices a and b both of size NxN find if matrix a can be transformed to matrix b by rotating it 90deg , 180deg , 270deg if so print TRUE else print FALSE.c
================================================
#include<stdio.h>
int main(void)
{
int a[20][20],b[20][20],i,j,r1,c1,r2,c2;
printf("Row and coloumn : ");
scanf("%d %d",&r1,&c1);
printf("Elements to array : ");
for(i=0;i<r1;i++)
for(j=0;j<c1;j++)
scanf("%d",&a[i][j]);
printf("Row and coloumn : ");
scanf("%d %d",&r2,&c2);
printf("Elements to array : ");
for(i=0;i<r2;i++)
for(j=0;j<c2;j++)
scanf("%d",&b[i][j]);
printf("Array A Elements : \n");
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
printf("%d ",a[i][j]);
printf("\n");
}
printf("Array B Elements : \n");
for(i=0;i<r2;i++)
{
for(j=0;j<c2;j++)
printf("%d ",b[i][j]);
printf("\n");
}
if(r2==c1 && c2==r1)
{
for(i=c1-1;i>=0;i--)
for(j=0;j<r1;j++)
if(a[j][i]!=b[c1-1-i][j])
goto NEXT1;
printf("\nTRUE (90 Deg)\n");
return;
}
if(r2==r1&&c2==c1)
{
for(i=r1-1;i>=0;i--)
for(j=c1-1;j>=0;j--)
if(a[i][j]!=b[r1-1-i][c1-1-j])
goto NEXT2;
printf("\nTRUE (180 Deg)\n");
return;
}
NEXT1:
if(r2==c1 &&c2==r1)
{
for(i=0;i<c1;i++)
for(j=r1-1;j>=0;j--)
if(a[j][i]!=b[i][r1-1-j])
goto NEXT2;
printf("\nTRUE (270 Deg)\n");
return;
}
NEXT2:
printf("\nFALSE\n");
return 0;
}
================================================
FILE: Set 12-08.In addition to the above question you have to check if matrix a can be transformed by mirroring vertically or horizontally to matrix b..c
================================================
#include<stdio.h>
int main(void)
{
int a[20][20],b[20][20],i,j,r1,c1,r2,c2;
printf("Row and coloumn : ");
scanf("%d %d",&r1,&c1);
printf("Elements to array : ");
for(i=0;i<r1;i++)
for(j=0;j<c1;j++)
scanf("%d",&a[i][j]);
printf("Row and coloumn : ");
scanf("%d %d",&r2,&c2);
printf("Elements to array : ");
for(i=0;i<r2;i++)
for(j=0;j<c2;j++)
scanf("%d",&b[i][j]);
printf("Array A Elements : \n");
for(i=0;i<r1;i++)
{
for(j=0;j<c1;j++)
printf("%d ",a[i][j]);
printf("\n");
}
printf("Array B Elements : \n");
for(i=0;i<r2;i++)
{
for(j=0;j<c2;j++)
printf("%d ",b[i][j]);
printf("\n");
}
if(r2==c1 && c2==r1)
{
for(i=c1-1;i>=0;i--)
for(j=0;j<r1;j++)
if(a[j][i]!=b[c1-1-i][j])
goto NEXT1;
printf("\nTRUE (90 Deg)\n");
return;
}
if(r2==r1&&c2==c1)
{
for(i=r1-1;i>=0;i--)
for(j=c1-1;j>=0;j--)
if(a[i][j]!=b[r1-1-i][c1-1-j])
goto NEXT2;
printf("\nTRUE (180 Deg)\n");
return;
}
NEXT1:
if(r2==c1 &&c2==r1)
{
for(i=0;i<c1;i++)
for(j=r1-1;j>=0;j--)
if(a[j][i]!=b[i][r1-1-j])
goto NEXT4;
printf("\nTRUE (270 Deg)\n");
return;
}
NEXT2:
if(r2==r1&&c2==c1)
{
for(i=0;i<r1;i++)
for(j=c1-1;j>=0;j--)
if(a[i][j]!=b[i][c1-1-j])
goto NEXT3;
printf("\nTRUE (Horizontal Mirror)\n");
return;
}
NEXT3:
if(r2==r1&&c2==c1)
{
for(i=r1-1;i>=0;i--)
for(j=0;j<c1;j++)
if(a[i][j]!=b[r1-1-i][j])
goto NEXT4;
printf("\nTRUE (Vertical Mirror)\n");
return;
}
NEXT4:
printf("\nFALSE\n");
return 0;
}
================================================
FILE: Set 12-Qns
================================================
Zoho Interview Experience | Set 12 (On-Campus)
Recently ZOHO visited our campus for recruitment and i would like to share my experience.
Thanks to geeksforgeeks which contributed to most of my preparations..
Round 1 : TIME : 2hrs
I was expecting an aptitude written round .But they gave us 30 flowchart and asked us to go through each flowchart and the questions were based on the flowchart..Questions included finding the o/p of the flowchart , find the missing statement which when added produces the given o/p..If you concentrate and go through the flowchart it should be easy to crack the first round..
Round 2: TIME : 3hrs
They shortlisted 150 candidates from the first round..This was a programming round and consisted of straightforward questions..
1.Given two numbers a and b both < 200 we have to find the square numbers which lie between a and b(inclusive)
eg) i/p a = 20;b = 100;
o/p 25,36,49,64,81,100
2.Alternately sort an unsorted array..
eg) i/p {5,2,8,7,4,3,9}
o/p {9,2,8,3,7,4,5}
3. Given an array and a threshold value find the o/p
eg) i/p {5,8,10,13,6,2};threshold = 3;
o/p count = 17
explanation:
Number parts counts
5 {3,2} 2
8 {3,3,2} 3
10 {3,3,3,1} 4
13 {3,3,3,3,1} 5
6 {3,3} 2
2 {2} 1
4.a. Given two binary numbers add the two numbers in binary form without converting them to decimal value.
eg) a = 1010 b = 11001
o/p 100011
b.The two numbers were given in base n
eg) a = 123 b = 13 n = 4
o/p 202
5.Write a program to print the below pattern
for n = 6
1 7 12 16 19 21
2 8 13 17 20
3 9 14 18
4 10 15
5 11
6
6.Given bigger NxN matrix and a smaller MxM matrix print TRUE if the smaller matrix can be found in the bigger matrix else print FALSE
7.Given two matrices a and b both of size NxN find if matrix a can be transformed to matrix b by rotating it 90deg , 180deg , 270deg if so print TRUE else print FALSE
8 In addition to the above question you have to check if matrix a can be transformed by mirroring vertically or horizontally to matrix b.
I solved 7 questions .. Those who solved more than 5 were selected for the next round.
Round 3 : TIME : 3hrs
About 50 – 60 were shortlisted .. This round was also a programming round..
Questions were based of matrix transformation.Each question was an extension of the previous question in some way..There were 5 questions .. I solved only 2 🙁 But got selected for the next round , I think it was based on my performance on all previous rounds..
Round 4:
We had both HR and technical HR.
In technical HR if they found out that a candidate was not sure on some topic the candidate was asked questions on that topic for the rest of the round even after the candidate said he does not know that concept . In my case it was DBMS 🙁 The round also consisted of 3 puzzles ..they were easy to solve , i solved all of them..
In HR round we had a friendly chat ..They didn’t want candidates who were willing to quit the job after a few years and go for higher studies( obviously )..I was asked about my family and my hobbies..
After round 4 we had to wait for almost 5 hrs before the results were announced..There were 2 packages x and x+y.. I was offered the x package mostly because i didn’t do round 3 well but they said that if we prove ourselves during the internship they would change the package to x+y so looking forward to that 😉
Overall it was a good experience and i really appreciate ZOHO team for the amount of effort they invested in the interview process each round was both challenging and enjoyable in its own way
gitextract_5u_4w79b/ ├── .gitignore ├── LICENSE ├── README.md ├── Set 01 Qns.txt ├── Set 01-01.print the following pattern.c ├── Set 01-02.find sum of weights based on the following conditions.c ├── Set 01-03.Save the string in a two dimensional array and search for substring.c ├── Set 01-05.find no of grandchildren.c ├── Set 02-01.Alternate sorting.c ├── Set 02-01.Alternate sorting.py ├── Set 02-02.Remove unbalanced parentheses in a given expression.c ├── Set 02-02.Remove unbalanced parentheses in a given expression.py ├── Set 02-03.Form a number system with only 3 and 4.c ├── Set 02-qns ├── Set 03-01.program to give the following output.c ├── Set 03-02.sort the elements in odd positions in descending order and elements in ascending order.c ├── Set 03-03.program to print the following output for the given input.c ├── Set 03-05-01.two sorted arrays, merge them such that the elements are not repeated.c ├── Set 03-05-02.two sorted arrays, merge them such that the elements are not repeated.c ├── Set 03-Qns ├── Set 08 Qns ├── Set 08 Qns2 ├── Set 08-01.Spiral printing.c ├── Set 08-02.Two strings of equal length are given print the mismatched ones..c ├── Set 08-03.Get a number and check whether its palindrome do not use arrays and string manipulations.c ├── Set 12-01.Given two numbers a and b both < 200 we have to find the square numbers which lie between a and b.c ├── Set 12-03.Given an array and a threshold value find the output.c ├── Set 12-05.Write a program to print the below pattern.c ├── Set 12-06.Given bigger NxN matrix and a smaller MxM matrix print TRUE if the smaller matrix can be found in the bigger matrix else print FALSE.c ├── Set 12-07.Given two matrices a and b both of size NxN find if matrix a can be transformed to matrix b by rotating it 90deg , 180deg , 270deg if so print TRUE else print FALSE.c ├── Set 12-08.In addition to the above question you have to check if matrix a can be transformed by mirroring vertically or horizontally to matrix b..c └── Set 12-Qns
SYMBOL INDEX (26 symbols across 23 files) FILE: Set 01-01.print the following pattern.c function main (line 11) | int main(void) FILE: Set 01-02.find sum of weights based on the following conditions.c function main (line 14) | int main(void) function check (line 37) | int check(int n) FILE: Set 01-03.Save the string in a two dimensional array and search for substring.c function main (line 16) | int main(void) function sqt (line 70) | int sqt(float n) FILE: Set 01-05.find no of grandchildren.c function main (line 13) | int main(void) FILE: Set 02-01.Alternate sorting.c function main (line 6) | int main(void) FILE: Set 02-01.Alternate sorting.py function main (line 6) | def main(): FILE: Set 02-02.Remove unbalanced parentheses in a given expression.c function main (line 20) | int main(void) FILE: Set 02-02.Remove unbalanced parentheses in a given expression.py function remove (line 4) | def remove(s,index): function main (line 8) | def main(): FILE: Set 02-03.Form a number system with only 3 and 4.c function main (line 5) | int main(void) FILE: Set 03-01.program to give the following output.c function main (line 10) | int main(void) FILE: Set 03-02.sort the elements in odd positions in descending order and elements in ascending order.c function main (line 10) | int main(void) FILE: Set 03-03.program to print the following output for the given input.c function main (line 27) | int main(void) FILE: Set 03-05-01.two sorted arrays, merge them such that the elements are not repeated.c function main (line 11) | int main(void) FILE: Set 03-05-02.two sorted arrays, merge them such that the elements are not repeated.c function main (line 10) | int main(void) FILE: Set 08-01.Spiral printing.c function main (line 2) | int main(void) FILE: Set 08-02.Two strings of equal length are given print the mismatched ones..c function main (line 2) | int main(void) FILE: Set 08-03.Get a number and check whether its palindrome do not use arrays and string manipulations.c function main (line 2) | int main(void) FILE: Set 12-01.Given two numbers a and b both < 200 we have to find the square numbers which lie between a and b.c function main (line 2) | int main(void) FILE: Set 12-03.Given an array and a threshold value find the output.c function main (line 2) | int main(void) FILE: Set 12-05.Write a program to print the below pattern.c function main (line 2) | int main(void) FILE: Set 12-06.Given bigger NxN matrix and a smaller MxM matrix print TRUE if the smaller matrix can be found in the bigger matrix else print FALSE.c function main (line 3) | int main(void) FILE: Set 12-07.Given two matrices a and b both of size NxN find if matrix a can be transformed to matrix b by rotating it 90deg , 180deg , 270deg if so print TRUE else print FALSE.c function main (line 2) | int main(void) FILE: Set 12-08.In addition to the above question you have to check if matrix a can be transformed by mirroring vertically or horizontally to matrix b..c function main (line 3) | int main(void)
Condensed preview — 32 files, each showing path, character count, and a content snippet. Download the .json file or copy for the full structured content (85K chars).
[
{
"path": ".gitignore",
"chars": 430,
"preview": "# Prerequisites\n*.d\n\n# Object files\n*.o\n*.ko\n*.obj\n*.elf\n\n# Linker output\n*.ilk\n*.map\n*.exp\n\n# Precompiled Headers\n*.gch"
},
{
"path": "LICENSE",
"chars": 35141,
"preview": " GNU GENERAL PUBLIC LICENSE\n Version 3, 29 June 2007\n\n Copyright (C) 2007 Free "
},
{
"path": "README.md",
"chars": 61,
"preview": "# Zoho-Interview-questions\nprevious zoho interview questions\n"
},
{
"path": "Set 01 Qns.txt",
"chars": 1687,
"preview": "SET 1\n\nSecond Round: (Normal Programming round)\n1. Print the word with odd letters as\n\nP M\n R A\n O R\n "
},
{
"path": "Set 01-01.print the following pattern.c",
"chars": 877,
"preview": " /* To print the following pattern\n \tP M\n R A\n O R\n G\n"
},
{
"path": "Set 01-02.find sum of weights based on the following conditions.c",
"chars": 1195,
"preview": "/* Given a set of numbers like <10,36,54,89,12> we want to find sum of weights based on the following conditions\n 1. "
},
{
"path": "Set 01-03.Save the string in a two dimensional array and search for substring.c",
"chars": 1880,
"preview": "/* Save the string “WELCOMETOZOHOCORPORATION” in a two dimensional array and search for substring like “too” in the two "
},
{
"path": "Set 01-05.find no of grandchildren.c",
"chars": 1768,
"preview": "/* Given a two dimensional array of string like\n\n <”luke”, “shaw”>\n <”wayne”, “rooney”>\n <”rooney”, “ronaldo”>\n <”s"
},
{
"path": "Set 02-01.Alternate sorting.c",
"chars": 1148,
"preview": "/* Alternate sorting: Given an array of integers, rearrange the array in such a way that the first element is first max"
},
{
"path": "Set 02-01.Alternate sorting.py",
"chars": 786,
"preview": "#!/usr/bin/python\n''' Alternate sorting: Given an array of integers, rearrange the array in such a way that the first el"
},
{
"path": "Set 02-02.Remove unbalanced parentheses in a given expression.c",
"chars": 1059,
"preview": "/* Remove unbalanced parentheses in a given expression.\n\n Eg.) Input : ((abc)((de))\n Output : ((abc)(de)) \n "
},
{
"path": "Set 02-02.Remove unbalanced parentheses in a given expression.py",
"chars": 886,
"preview": "#!/usr/bin/python\n\n#Remove unbalanced parentheses in a given expression\ndef remove(s,index):\n s=s[:index]+s[index+1:]"
},
{
"path": "Set 02-03.Form a number system with only 3 and 4.c",
"chars": 1165,
"preview": "/* C) Form a number system with only 3 and 4. Find the nth number of the number system.\nEg.) The numbers are: 3, 4, 33, "
},
{
"path": "Set 02-qns",
"chars": 3951,
"preview": "Set 2\n\n1) First Round : Written\n\n40 C output questions. 2 Hours.\n30 1Mark and 10 2Mark questions. IT WAS NOT MCQ. The qu"
},
{
"path": "Set 03-01.program to give the following output.c",
"chars": 1004,
"preview": "/* 1. Write a program to give the following output for the given input\n\nEg 1: Input: a1b10\n Output: abbbbbbbbbb\nEg"
},
{
"path": "Set 03-02.sort the elements in odd positions in descending order and elements in ascending order.c",
"chars": 761,
"preview": "/* 2. Write a program to sort the elements in odd positions in descending order and elements in ascending order\n\nEg 1: I"
},
{
"path": "Set 03-03.program to print the following output for the given input.c",
"chars": 1057,
"preview": "/*3. Write a program to print the following output for the given input. You can assume the string is of odd length\n\nEg 1"
},
{
"path": "Set 03-05-01.two sorted arrays, merge them such that the elements are not repeated.c",
"chars": 2611,
"preview": "/* 5. Given two sorted arrays, merge them such that the elements are not repeated\n\nEg 1: Input:\n Array 1: 2,4,5,6"
},
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"path": "Set 03-05-02.two sorted arrays, merge them such that the elements are not repeated.c",
"chars": 1678,
"preview": "/*5. Given two sorted arrays, merge them such that the elements are not repeated\n\nEg 1: Input:\n Array 1: 2,4,5,6,"
},
{
"path": "Set 03-Qns",
"chars": 5709,
"preview": "Set 3\n\nROUND 1: WRITTEN\nAPTITUDE(1 hr and 20 minutes-20 questions): Problems on average, probability, time & distance, a"
},
{
"path": "Set 08 Qns",
"chars": 3042,
"preview": "\nZoho Interview | Set 8 (Off-Campus Drive for Project Trainee)\n\nFirst Round:\nWritten, pen paper based. The candidate has"
},
{
"path": "Set 08 Qns2",
"chars": 1320,
"preview": "\nZoho Interview | Set 8 (On-Campus)\n\nROUND 1: Aptitude questions – both Quantitative aptitude and in programming. they w"
},
{
"path": "Set 08-01.Spiral printing.c",
"chars": 433,
"preview": "#include<stdio.h>\nint main(void)\n{\n\tint i,j,n;\n\tprintf(\"Limit : \");\n\tscanf(\"%d\",&n);\n\tfor(i=n;i>=1;i--)\n\t{\n\t\tfor(j=n;j"
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{
"path": "Set 08-02.Two strings of equal length are given print the mismatched ones..c",
"chars": 495,
"preview": "#include<stdio.h>\nint main(void)\n{\n\tchar a[50],b[50];\n\tint i,j,n,st=0;\n\tprintf(\"Array size : \");\n\tscanf(\"%d\",&n);\n\tprin"
},
{
"path": "Set 08-03.Get a number and check whether its palindrome do not use arrays and string manipulations.c",
"chars": 346,
"preview": "#include<stdio.h>\nint main(void)\n{\n\tint n,i,j=0,temp;\n\tprintf(\"Enter a Number : \");\n\tscanf(\"%d\",&n);\n\n\tfor(i=sizeof(int)"
},
{
"path": "Set 12-01.Given two numbers a and b both < 200 we have to find the square numbers which lie between a and b.c",
"chars": 276,
"preview": "#include<stdio.h>\nint main(void)\n{\nint a,b,i;\nprintf(\"Lower NUmber : \");\nscanf(\"%d\",&a);\nprintf(\"Upper NUmber : \");\nscan"
},
{
"path": "Set 12-03.Given an array and a threshold value find the output.c",
"chars": 515,
"preview": "#include<stdio.h>\nint main(void)\n{\nint a[100],i,th,n,count=0,sum,temp;\nprintf(\"Array size : \");\nscanf(\"%d\",&n);\nprintf(\""
},
{
"path": "Set 12-05.Write a program to print the below pattern.c",
"chars": 198,
"preview": "#include<stdio.h>\nint main(void)\n{\n\tint n,i,j,k;\n\tprintf(\"Limit : \");\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tk=i+1;\n\t\tf"
},
{
"path": "Set 12-06.Given bigger NxN matrix and a smaller MxM matrix print TRUE if the smaller matrix can be found in the bigger matrix else print FALSE.c",
"chars": 914,
"preview": "\n#include<stdio.h>\nint main(void)\n{\nint a[50][50],b[50][50],r1,c1,r2,c2,i,j,k,l;\nprintf(\"Array 1 size : \");\nscanf(\"%d%d\""
},
{
"path": "Set 12-07.Given two matrices a and b both of size NxN find if matrix a can be transformed to matrix b by rotating it 90deg , 180deg , 270deg if so print TRUE else print FALSE.c",
"chars": 1083,
"preview": "#include<stdio.h>\nint main(void)\n{\nint a[20][20],b[20][20],i,j,r1,c1,r2,c2;\nprintf(\"Row and coloumn : \");\nscanf(\"%d %d"
},
{
"path": "Set 12-08.In addition to the above question you have to check if matrix a can be transformed by mirroring vertically or horizontally to matrix b..c",
"chars": 1401,
"preview": "\n#include<stdio.h>\nint main(void)\n{\nint a[20][20],b[20][20],i,j,r1,c1,r2,c2;\nprintf(\"Row and coloumn : \");\nscanf(\"%d %"
},
{
"path": "Set 12-Qns",
"chars": 3780,
"preview": "Zoho Interview Experience | Set 12 (On-Campus)\nRecently ZOHO visited our campus for recruitment and i would like to shar"
}
]
About this extraction
This page contains the full source code of the amalpoulose/Zoho-Interview-questions GitHub repository, extracted and formatted as plain text for AI agents and large language models (LLMs). The extraction includes 32 files (76.8 KB), approximately 22.3k tokens, and a symbol index with 26 extracted functions, classes, methods, constants, and types. Use this with OpenClaw, Claude, ChatGPT, Cursor, Windsurf, or any other AI tool that accepts text input. You can copy the full output to your clipboard or download it as a .txt file.
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